j^2-10j+25=1

Solution for j^2-10j+25=1 equation:

Simplifying
j2 + -10j + 25 = 1

Reorder the terms:
25 + -10j + j2 = 1

Solving
25 + -10j + j2 = 1

Solving for variable 'j'.

Reorder the terms:
25 + -1 + -10j + j2 = 1 + -1

Combine like terms: 25 + -1 = 24
24 + -10j + j2 = 1 + -1

Combine like terms: 1 + -1 = 0
24 + -10j + j2 = 0

Factor a trinomial.
(4 + -1j)(6 + -1j) = 0

Subproblem 1
Set the factor '(4 + -1j)' equal to zero and attempt to solve:

Simplifying
4 + -1j = 0

Solving
4 + -1j = 0

Move all terms containing j to the left, all other terms to the right.

Add '-4' to each side of the equation.
4 + -4 + -1j = 0 + -4

Combine like terms: 4 + -4 = 0
0 + -1j = 0 + -4
-1j = 0 + -4

Combine like terms: 0 + -4 = -4
-1j = -4

Divide each side by '-1'.
j = 4

Simplifying
j = 4
Subproblem 2
Set the factor '(6 + -1j)' equal to zero and attempt to solve:

Simplifying
6 + -1j = 0

Solving
6 + -1j = 0

Move all terms containing j to the left, all other terms to the right.

Add '-6' to each side of the equation.
6 + -6 + -1j = 0 + -6

Combine like terms: 6 + -6 = 0
0 + -1j = 0 + -6
-1j = 0 + -6

Combine like terms: 0 + -6 = -6
-1j = -6

Divide each side by '-1'.
j = 6

Simplifying
j = 6
Solution
j = {4, 6}